On Fri, Jul 28, 2000 at 09:47:08AM +0200, Martin Cracauer wrote:
> ! if (c >= CTLESC && c <= CTLQUOTEMARK) {
> synentry = CWORD;
> ! fprintf(stderr,
> ! "Warning: internal control character in "
> ! "literal text, using '?' instead\n");
> ! c = '?';
> ! }
I disagree. It is not the fix, just admitting the bug. Better try to fix it via
some escaping of control characters via some prefix char. Bash is 8bit clean
in that place, f.e.
--
Andrey A. Chernov
<ache@nagual.pp.ru>
http://ache.pp.ru/
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